(D) The conductance of an electrolytic solution depends on the number of ions present and their mobility. When the temperature of an electrolytic solu

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Increases because the electrolyte is dissociated more

(D) The conductance of an electrolytic solution depends on the number of ions present and their mobility. When the temperature of an electrolytic solution is increased,the kinetic energy of the ions increases,which increases their mobility. Additionally,for weak electrolytes,the degree of dissociation increases with an increase in temperature,leading to a higher number of ions. Therefore,the conductance of the solution increases.

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Easy

When a solution of an electrolyte is heated,the conductance of the solution:

A
Increases because the electrolyte conducts better
B
Decreases because of the increased heat
C
Decreases because the dissociation of the electrolyte is suppressed
D
Increases because the electrolyte is dissociated more

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Conductor and Conductance and Cell constant

The specific conductivity of $N/10$ $KCl$ solution at $20\,^oC$ is $0.0212\,ohm^{-1}\,cm^{-1}$ and the resistance of the cell containing this solution at $20\,^oC$ is $55\,ohm$. The cell constant is ............. $cm^{-1}$.

MediumAIIMS 1999

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At $298 \ K$,the resistance of a $0.01 \ N$ electrolyte solution is $210 \ \Omega$. If the cell constant of the conductivity cell used is $0.66 \ cm^{-1}$,what is the equivalent conductivity of the solution in $mho \ cm^2 \ eq^{-1}$?

Easy

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$0.2\% (w/v)$ solution of $NaOH$ is measured to have resistivity $870.0 \ m\Omega \ m$. The molar conductivity of the solution will be $........ \times 10^2 \ mS \ dm^2 \ mol^{-1}$. $(Nearest \ integer)$

DifficultJEE MAIN 2025

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Calculate $\Lambda _{HOAc}^{\infty }$ using appropriate molar conductances of the electrolytes listed below at infinite dilution in $H_2O$ at $25\ ^oC$.

Electrolyte $\Lambda ^{\infty } (S\ cm^2\ mol^{-1})$

$KCl$ $149.9$

$KNO_3$ $145.0$

$HCl$ $426.2$

$NaOAc$ $91.0$

$NaCl$ $126.5$

Electrolyte	$\Lambda ^{\infty } (S\ cm^2\ mol^{-1})$
$KCl$	$149.9$
$KNO_3$	$145.0$
$HCl$	$426.2$
$NaOAc$	$91.0$
$NaCl$	$126.5$

MediumAIEEE 2005

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Limiting molar conductivity of $CH_3COOH$ (i.e.,$\Lambda^o_{m(CH_3COOH)}$) is equal to:

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When a solution of an electrolyte is heated,the conductance of the solution:

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The specific conductivity of $N/10$ $KCl$ solution at $20\,^oC$ is $0.0212\,ohm^{-1}\,cm^{-1}$ and the resistance of the cell containing this solution at $20\,^oC$ is $55\,ohm$. The cell constant is ............. $cm^{-1}$.

At $298 \ K$,the resistance of a $0.01 \ N$ electrolyte solution is $210 \ \Omega$. If the cell constant of the conductivity cell used is $0.66 \ cm^{-1}$,what is the equivalent conductivity of the solution in $mho \ cm^2 \ eq^{-1}$?

$0.2\% (w/v)$ solution of $NaOH$ is measured to have resistivity $870.0 \ m\Omega \ m$. The molar conductivity of the solution will be $........ \times 10^2 \ mS \ dm^2 \ mol^{-1}$. $(Nearest \ integer)$

Calculate $\Lambda _{HOAc}^{\infty }$ using appropriate molar conductances of the electrolytes listed below at infinite dilution in $H_2O$ at $25\ ^oC$. Electrolyte $\Lambda ^{\infty } (S\ cm^2\ mol^{-1})$ $KCl$ $149.9$ $KNO_3$ $145.0$ $HCl$ $426.2$ $NaOAc$ $91.0$ $NaCl$ $126.5$

Limiting molar conductivity of $CH_3COOH$ (i.e.,$\Lambda^o_{m(CH_3COOH)}$) is equal to:

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Calculate $\Lambda _{HOAc}^{\infty }$ using appropriate molar conductances of the electrolytes listed below at infinite dilution in $H_2O$ at $25\ ^oC$.

Electrolyte $\Lambda ^{\infty } (S\ cm^2\ mol^{-1})$

$KCl$ $149.9$

$KNO_3$ $145.0$

$HCl$ $426.2$

$NaOAc$ $91.0$

$NaCl$ $126.5$