When a positively charged particle enters a u | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic force on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.$1$. If the velocity $\vec{v}$ is parallel or anti-para

Vedclass · Accepted Answer

any one of $(1)$,$(2)$ and $(3)$

Vedclass · Answer

(D) The magnetic force on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.$1$. If the velocity $\vec{v}$ is parallel or anti-parallel to the magnetic field $\vec{B}$,then $\vec{v} 	imes \vec{B} = 0$,so $\vec{F} = 0$. The particle continues in a straight line.$2$. If the velocity $\vec{v}$ is perpendicular to the magnetic field $\vec{B}$,the force acts as a centripetal force,causing the particle to move in a circle.$3$. If the velocity $\vec{v}$ makes an angle $	heta$ (where $	heta 
eq 0^\circ, 90^\circ, 180^\circ$) with the magnetic field $\vec{B}$,the velocity component parallel to the field remains constant,while the perpendicular component causes circular motion. This results in a helical trajectory.Therefore,all three trajectories are possible depending on the angle between $\vec{v}$ and $\vec{B}$.

When a positively charged particle enters a uniform magnetic field with uniform velocity,its trajectory can be :
$(1)$ a straight line
$(2)$ a circle
$(3)$ a helix

Similar Questions

Which one of the following equations represents the variation of viscosity coefficient $(\eta)$ with temperature $(T)$?

The radius of the smallest electron orbit in a hydrogen-like ion is $(0.51 \times 10^{-10} / 4) \text{ m}$. This ion is:

Which of the following properties is $NOT$ exhibited by $Carbon$?

Smooth muscles are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

When a positively charged particle enters a uniform magnetic field with uniform velocity,its trajectory can be :$(1)$ a straight line$(2)$ a circle$(3)$ a helix