When a piece of sodium is added to water,it r | vedclass

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Question

(A) The reaction between sodium $(Na)$ and water $(H_2O)$ is: $2Na(s) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g)$.In this reaction,the oxidation state

Vedclass · Accepted Answer

Sodium loses electrons.

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(A) The reaction between sodium $(Na)$ and water $(H_2O)$ is: $2Na(s) + 2H_2O(l) \rightarrow 2NaOH(aq) + H_2(g)$.In this reaction,the oxidation state of $Na$ increases from $0$ to $+1$ (it loses electrons,so it is oxidized).The oxidation state of $H$ in $H_2O$ decreases from $+1$ to $0$ (it gains electrons,so it is reduced).Since $Na$ loses electrons,it acts as a reducing agent,and the water molecules are reduced to produce $H_2$ gas.

When a piece of sodium is added to water,it reacts to produce hydrogen gas because:

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