When a piece of polythene is rubbed with wool | vedclass

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(D) The charge on the polythene is given by $q = 4 	imes 10^{-7} \ C$. According to the quantization of charge,the total charge $q$ is given by $q =

Vedclass · Accepted Answer

$2.5 	imes 10^{12}$

Vedclass · Answer

(D) The charge on the polythene is given by $q = 4 	imes 10^{-7} \ C$. According to the quantization of charge,the total charge $q$ is given by $q = Ne$,where $N$ is the number of electrons and $e$ is the elementary charge. Given $e = 1.6 	imes 10^{-19} \ C$. To find the number of electrons $N$,we use the formula $N = \frac{q}{e}$. Substituting the values: $N = \frac{4 	imes 10^{-7}}{1.6 	imes 10^{-19}}$. $N = \frac{4}{1.6} 	imes 10^{-7 - (-19)} = 2.5 	imes 10^{12}$. Thus,the number of electrons transferred is $2.5 	imes 10^{12}$.

When a piece of polythene is rubbed with wool,a negative charge of $4 \times 10^{-7} \ C$ is developed on the polythene. The number of electrons transferred from wool to polythene is $\left[e = 1.6 \times 10^{-19} \ C\right]$.

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