When a metallic surface is illuminated with radiation of wavelength $\lambda$,the stopping potential is $V$. If the same surface is illuminated with radiation of wavelength $2\lambda$,the stopping potential is $\frac{V}{4}$. The threshold wavelength for the metallic surface is:

  • A
    $4\lambda$
  • B
    $5\lambda$
  • C
    $\frac{5}{2}\lambda$
  • D
    $3\lambda$

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