When a metal X is treated with cold water,it | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $(i)$ The molecular formula of $Y$ is $XOH$ and its molecular mass is $40$. The atomic mass of $O$ is $16$ and $H$ is $1$. Thus,$X + 16 + 1 = 40$,

Vedclass · Accepted Answer

$X = Na, Y = NaOH, Z = H_2$

Vedclass · Answer

(A) $(i)$ The molecular formula of $Y$ is $XOH$ and its molecular mass is $40$. The atomic mass of $O$ is $16$ and $H$ is $1$. Thus,$X + 16 + 1 = 40$,which gives $X = 23$. The element with atomic mass $23$ is Sodium $(Na)$.$(ii)$ When sodium $(Na)$ reacts with cold water,it forms sodium hydroxide $(NaOH)$ and releases hydrogen gas $(H_2)$.$(iii)$ Hydrogen gas $(H_2)$ is highly flammable and catches fire easily.$(iv)$ Therefore,$X = Na$,$Y = NaOH$,and $Z = H_2$.

When a metal $X$ is treated with cold water,it gives a basic salt $Y$ with molecular formula $XOH$ (Molecular mass $= 40$) and liberates a gas $Z$ which easily catches fire. Identify $X, Y, Z$.

Similar Questions

Which method is used for the refining of metals having low melting points?

Which of the following methods is used for the concentration of ore?

State whether the following statement is true or false:
The elements or compounds,which occur naturally in the earth's crust,are known as minerals.

Which metal oxide dissolves in water to form an alkali?

Which of the following is an alloy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module