Easy
When a mercury drop of radius $R$ breaks into $n$ droplets of equal size,the radius $r$ of each droplet is
- A$r=\frac{R}{\sqrt{n}}$
- B$r=\frac{R}{n}$
- C$r=\frac{R}{n^{\frac{1}{3}}}$
- D$r=R n^{\frac{1}{3}}$
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