When a helium nucleus covers a circle of radi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Charge on helium nucleus, $q = +2e = 2 	imes 1.6 	imes 10^{-19} \,C = 3.2 	imes 10^{-19} \,C$. Radius of the circle, $r = 0.8 \,m$. Time period

Vedclass · Accepted Answer

$\mu_0 	imes 10^{-19} \,T$

Vedclass · Answer

(B) Charge on helium nucleus, $q = +2e = 2 	imes 1.6 	imes 10^{-19} \,C = 3.2 	imes 10^{-19} \,C$. Radius of the circle, $r = 0.8 \,m$. Time period, $T = 2 \,s$. Therefore, the current associated with the moving helium nucleus is $I = \frac{q}{T} = \frac{3.2 	imes 10^{-19} \,C}{2 \,s} = 1.6 	imes 10^{-19} \,A$. The magnetic field at the centre of a circular loop is given by $B = \frac{\mu_0 I}{2r}$. Substituting the values, $B = \frac{\mu_0 	imes 1.6 	imes 10^{-19}}{2 	imes 0.8} = \frac{\mu_0 	imes 1.6 	imes 10^{-19}}{1.6} = \mu_0 	imes 10^{-19} \,T$.

When a helium nucleus covers a circle of radius $0.8 \,m$ in $2 \,s$, find the value of magnetic field $B$ at the centre of the circle.

Similar Questions

$A$ negative charge is given to a non-conducting loop and the loop is rotated in the plane of paper about its centre as shown in the figure. The magnetic field produced by the ring affects a small magnet placed above the ring in the same plane.

$A$ non-planar loop of conducting wire carrying a current $I$ is placed as shown in the figure. Each of the straight sections of the loop is of length $2a$. The magnetic field due to this loop at the point $P(a, 0, a)$ points in the direction:

The dimensions of the ratio of magnetic flux $(\phi)$ and permeability $(\mu)$ are

Let $B_1$ be the magnitude of the magnetic field at the center of a circular coil of radius $R$ carrying current $I$. Let $B_2$ be the magnitude of the magnetic field at an axial distance $x$ from the center. For $x : R = 3 : 4$,the ratio $\frac{B_2}{B_1}$ is:

$Weber/m^2$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module