When a coil is connected to a $d.c.$ source of $e.m.f.$ $12 \ V$,the current of $4 \ A$ flows in it. If the same coil is connected to a $12 \ V, 50 \ Hz$ $a.c.$ source,the current flowing in it is $2.4 \ A$. The self-inductance of the coil will be:

  • A
    $48 \ H$
  • B
    $12 \ H$
  • C
    $\frac{4}{\pi} \times 10^{-2} \ H$
  • D
    $\frac{8}{\pi} \times 10^{-2} \ H$

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In a series $LCR$ circuit, the potential drop across $L, C$ and $R$ respectively are $40 \,V, 120 \,V$ and $60 \,V$. Then the source voltage is (in $\,V$)

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