When a capacitor is connected to a battery,

The charge stored by the capacitor $C$ in the given circuit in the steady state is . . . . . . $\mu C$.

In the given circuit,the charge on the capacitors of capacitance $10\,\mu F$ and $24\,\mu F$ in the steady state will be:

In the circuit shown in the figure,the switch $S$ is initially open and the capacitor is initially uncharged. $I_1, I_2$ and $I_3$ represent the current in the resistance $2\,\Omega, 8\,\Omega$ and $4\,\Omega$ respectively.

$A$ capacitor of capacity $C$ is charged to a steady potential difference $V$ and connected in series with an open key and a pure resistor $R$. At time $t = 0$,the key is closed. If $I$ is the current at time $t$,a plot of $\log I$ against $t$ is as shown in $(1)$ in the graph. Later,one of the parameters,i.e.,$V, R,$ or $C$,is changed while keeping the other two constant,and the graph $(2)$ is recorded. Then:

The charge on a capacitor of capacitance $10\,\mu F$ connected as shown in the figure is.......$\mu C$