When a capacitor is connected in series with an $LR$ circuit,the alternating current flowing in the circuit

An oscillating circuit consists of a capacitor with capacitance $C = 10 \, \mu F$, a coil with inductance $L = 6.0 \, \mu H$, and active resistance $R = 10 \, \Omega$. The mean power that should be fed to the circuit to maintain undamped harmonic oscillations with an external driving source of frequency $f = 50 \, Hz$ and peak voltage $V_m = 280 \, V$ is:

An alternating voltage of frequency $\omega$ is induced in an electric circuit consisting of an inductance $L$ and capacitance $C$,connected in parallel. Then across the inductance coil:

When the $rms$ voltages $V_L, V_C$ and $V_R$ are measured respectively across the inductor $L$,the capacitor $C$ and the resistor $R$ in a series $LCR$ circuit connected to an $AC$ source,it is found that the ratio $V_L : V_C : V_R = 1 : 2 : 3$. If the $rms$ voltage of the $AC$ source is $100 \, V$,the $V_R$ is close to........$V$

An inductor of $10 \text{ mH}$,capacitor of $0.1 \text{ } \mu\text{F}$ and a resistor of $100 \text{ } \Omega$ are connected in series across an $a.c.$ power supply of $220 \text{ V}$,$70 \text{ Hz}$. The power factor of the given circuit is $0.5$. The difference between the inductive reactance and capacitive reactance is $\sqrt{3}\alpha \text{ } \Omega$. The value of $\alpha$ is . . . . . . .

When $L$, $C$, and $R$ are connected in series with an $AC$ source of frequency $f$, the current leads the voltage by a phase angle of $45^{\circ}$. What is the value of $C$?