When a body is taken from the pole to the equ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The acceleration due to gravity $g'$ at a latitude $\lambda$ is given by the formula: $g' = g - R \omega^2 \cos^2 \lambda$,where $\omega$ is the a

Vedclass · Accepted Answer

Decreases

Vedclass · Answer

(C) The acceleration due to gravity $g'$ at a latitude $\lambda$ is given by the formula: $g' = g - R \omega^2 \cos^2 \lambda$,where $\omega$ is the angular velocity of the Earth's rotation and $R$ is the radius of the Earth.At the poles,the latitude $\lambda = 90^\circ$. Substituting this into the formula: $g_{	ext{pole}} = g - R \omega^2 \cos^2(90^\circ) = g - 0 = g$.At the equator,the latitude $\lambda = 0^\circ$. Substituting this into the formula: $g_{	ext{equator}} = g - R \omega^2 \cos^2(0^\circ) = g - R \omega^2$.Since $g - R \omega^2 Weight is defined as $W = mg$. Since $g$ decreases when moving from the pole to the equator,the weight of the body decreases.

When a body is taken from the pole to the equator,its weight:

Similar Questions

The equation of the bisectors of the angle between the lines represented by $3 x^2-5 x y+4 y^2=0$ is

The coefficient of apparent expansion of a liquid when determined using two different vessels $A$ and $B$ are $\gamma_1$ and $\gamma_2$ respectively. If the coefficient of linear expansion of the vessel $A$ is $\alpha$,then find the coefficient of linear expansion of vessel $B$.

If the lines,joining the origin to the points of intersection of the curve $2x^2 - 2xy + 3y^2 + 2x - y - 1 = 0$ and the line $x + 2y = k$,are at right angles,then $k^2$ equals

An organic compound containing $C$ and $H$ has $92.3 \%$ of carbon. Its empirical formula is:

$A$ homogeneous equation of second degree in $x$ and $y$ represents which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module