When a big drop of water is formed from n sma | vedclass

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(D) Let $T$ be the surface tension of water.The surface energy of one small drop is $U_s = 4 \pi r^2 T$.The surface energy of $n$ small drops is $n U_

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$\frac{4 R^2}{r^2}$

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(D) Let $T$ be the surface tension of water.The surface energy of one small drop is $U_s = 4 \pi r^2 T$.The surface energy of $n$ small drops is $n U_s = n(4 \pi r^2 T)$.The surface energy of the bigger drop is $E = 4 \pi R^2 T$.The energy loss is given by the difference between the initial surface energy and the final surface energy:$	ext{Energy Loss} = n(4 \pi r^2 T) - 4 \pi R^2 T = 3E$.Since $E = 4 \pi R^2 T$,we have:$n(4 \pi r^2 T) - 4 \pi R^2 T = 3(4 \pi R^2 T)$.$n(4 \pi r^2 T) = 4(4 \pi R^2 T)$.$n r^2 = 4 R^2$.$n = 4 \frac{R^2}{r^2}$.

When a big drop of water is formed from $n$ small drops of water,the energy loss is $3E$,where $E$ is the energy of the bigger drop. If $R$ is the radius of the bigger drop and $r$ is the radius of the smaller drop,then the number of smaller drops $(n)$ is:

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