When {10^{19}} electrons are removed from a n | vedclass

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(B) The quantization of electric charge is given by the formula $Q = ne$,where $n$ is the number of electrons removed or added and $e$ is the elementa

Vedclass · Accepted Answer

$+1.6 \, C$

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(B) The quantization of electric charge is given by the formula $Q = ne$,where $n$ is the number of electrons removed or added and $e$ is the elementary charge $(e \approx 1.6 	imes 10^{-19} \, C)$.Since electrons are removed from the neutral metal plate,the plate becomes positively charged.Given $n = 10^{19}$ and $e = 1.6 	imes 10^{-19} \, C$,the charge $Q$ is:$Q = (+10^{19}) 	imes (1.6 	imes 10^{-19} \, C)$$Q = 1.6 	imes 10^{19-19} \, C$$Q = 1.6 	imes 10^0 \, C$$Q = +1.6 \, C$.

When ${10^{19}}$ electrons are removed from a neutral metal plate,the electric charge on it is

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