When 2-Chlorobutane is boiled with a concentr | vedclass

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Question

(B) The reaction of $2-$Chlorobutane with alcoholic $KOH$ is a dehydrohalogenation reaction (an elimination reaction,specifically $E2$).According to $

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$But-2-ene$

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(B) The reaction of $2-$Chlorobutane with alcoholic $KOH$ is a dehydrohalogenation reaction (an elimination reaction,specifically $E2$).According to $Saytzeff's$ rule,the major product is the more substituted alkene.$CH_3-CH_2-CHCl-CH_3 \xrightarrow{Alc. KOH} CH_3-CH=CH-CH_3$ ($But-2-ene$,major product) $+ CH_3-CH_2-CH=CH_2$ ($But-1-ene$,minor product).Therefore,$But-2-ene$ is the major product.

When $2-$Chlorobutane is boiled with a concentrated alcoholic solution of $KOH$,the major product formed is:

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