When 30 percent of one number is subtracted f | vedclass

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Question

(D) Let the first number be $x$ and the second number be $y$.According to the problem,when $30$ percent of the first number is subtracted from the sec

Vedclass · Accepted Answer

$2: 3$

Vedclass · Answer

(D) Let the first number be $x$ and the second number be $y$.According to the problem,when $30$ percent of the first number is subtracted from the second number,the result is four-fifth of the second number.This can be written as: $y - 0.3x = \frac{4}{5}y$.Rearranging the terms to group $y$ on one side: $y - \frac{4}{5}y = 0.3x$.Simplifying the left side: $\frac{1}{5}y = 0.3x$.Converting $0.3$ to a fraction: $\frac{1}{5}y = \frac{3}{10}x$.Multiplying both sides by $10$: $2y = 3x$.Therefore,the ratio of the first number $(x)$ to the second number $(y)$ is $\frac{x}{y} = \frac{2}{3}$,which is $2:3$.

When $30$ percent of one number is subtracted from another number,the second number reduces to its four-fifth. What is the ratio between the first and the second number respectively?

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