When CO_2 is passed into lime water,it turns | vedclass

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(B) When $CO_2$ is passed through lime water,it forms a white precipitate of calcium carbonate: $Ca(OH)_2 + CO_2 \xrightarrow{} CaCO_{3(s)} + H_2O$ Wh

Vedclass · Accepted Answer

Water-soluble $Ca(HCO_3)_2$ is formed

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(B) When $CO_2$ is passed through lime water,it forms a white precipitate of calcium carbonate: $Ca(OH)_2 + CO_2 \xrightarrow{} CaCO_{3(s)} + H_2O$ When excess $CO_2$ is passed,the insoluble $CaCO_3$ reacts with $CO_2$ and water to form water-soluble calcium bicarbonate: $CaCO_3 + CO_2 + H_2O \xrightarrow{} Ca(HCO_3)_2$ Thus,the milkiness disappears due to the formation of soluble $Ca(HCO_3)_2$.

When $CO_2$ is passed into lime water,it turns milky. When an excess of $CO_2$ is passed,the milkiness disappears because:

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