When 10^{-8} mol of HCl is dissolved in one | vedclass

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(D) The concentration of $H^+$ ions from $HCl$ is $10^{-8} \ M$. Since the concentration is very low,the contribution of $H^+$ ions from the auto-ioni

Vedclass · Accepted Answer

Below $7$

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(D) The concentration of $H^+$ ions from $HCl$ is $10^{-8} \ M$. Since the concentration is very low,the contribution of $H^+$ ions from the auto-ionization of water $(10^{-7} \ M)$ cannot be ignored. Total $[H^+] = [H^+]_{HCl} + [H^+]_{H_2O} = 10^{-8} + 10^{-7} = 1.1 	imes 10^{-7} \ M$. $pH = -\log[H^+] = -\log(1.1 	imes 10^{-7}) = 7 - \log(1.1) \approx 6.96$. Since $6.96 < 7$,the $pH$ of the solution is below $7$.

When $10^{-8} \ mol$ of $HCl$ is dissolved in one litre of water,the $pH$ of the solution will be

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