When 0.1 mol of CoCl_3(NH_3)_5 is treated wi | vedclass

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Question

(B) The reaction of the coordination compound with $AgNO_3$ precipitates only the chloride ions $(Cl^-)$ present outside the coordination sphere.Given

Vedclass · Accepted Answer

$[CoCl(NH_3)_5]Cl_2$

Vedclass · Answer

(B) The reaction of the coordination compound with $AgNO_3$ precipitates only the chloride ions $(Cl^-)$ present outside the coordination sphere.Given that $0.1 \ mol$ of the complex yields $0.2 \ mol$ of $AgCl$,the ratio of $AgCl$ to the complex is $2:1$.This indicates that there are $2$ ionizable $Cl^-$ ions outside the coordination sphere.Therefore,the formula is $[Co(NH_3)_5Cl]Cl_2$.

When $0.1 \ mol$ of $CoCl_3(NH_3)_5$ is treated with an excess of $AgNO_3$,$0.2 \ mol$ of $AgCl$ are obtained. The formula of the compound is:

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