When $FeCl_3$ reacts with $K_4[Fe(CN)_6]$,which of the following compounds is formed?

  • A
    Brown ring complex
  • B
    Sodium nitroprusside
  • C
    Turnbull's blue
  • D
    Prussian blue

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Ferric ion forms a Prussian blue precipitate due to the formation of

Which statement is true for sodium nitroprusside?

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In a complexometric titration of a metal ion with a ligand,the reaction is $M$ $(Metal-ion)$ + $L$ $(Ligand)$ $\to$ $C$ $(Complex)$. The end point is estimated spectrophotometrically (through light absorption). If '$M$' and '$C$' do not absorb light and only '$L$' absorbs,then the titration plot between absorbed light $(A)$ versus the volume of ligand '$L$' $(V)$ would look like:

$A$ reagent which gives a brilliant red precipitate with $Ni^{2+}$ ions in a basic medium is

The potassium ferrocyanide solution gives Prussian blue colour,when added to :

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