When {}_{92}U^{238} changes into {}_{82}Pb^{2 | vedclass

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(D) The change in mass number is $\Delta A = 238 - 206 = 32$.Each $\alpha$ decay reduces the mass number by $4$. Therefore,the number of $\alpha$ part

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$8$ and $6$

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(D) The change in mass number is $\Delta A = 238 - 206 = 32$.Each $\alpha$ decay reduces the mass number by $4$. Therefore,the number of $\alpha$ particles emitted is $N_{\alpha} = \frac{32}{4} = 8$.The change in atomic number due to $8$ $\alpha$ particles is $8 	imes 2 = 16$. The expected atomic number would be $92 - 16 = 76$.However,the final atomic number is $82$. The increase in atomic number is $82 - 76 = 6$.Each $\beta^-$ decay increases the atomic number by $1$. Therefore,the number of $\beta^-$ particles emitted is $N_{\beta} = 6$.Thus,$8$ $\alpha$ particles and $6$ $\beta^-$ particles are emitted.

When ${}_{92}U^{238}$ changes into ${}_{82}Pb^{206}$,the number of $\alpha$ and $\beta^-$ particles emitted are:

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