What will be the standard heat of reaction fo | vedclass

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(C) The standard heat of reaction $\Delta H_r^\circ$ is calculated using the formula: $\Delta H_r^\circ = \sum \Delta H_f^\circ(	ext{products}) - \su

Vedclass · Accepted Answer

$-1553.8 \ kJ/mol$

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(C) The standard heat of reaction $\Delta H_r^\circ$ is calculated using the formula: $\Delta H_r^\circ = \sum \Delta H_f^\circ(	ext{products}) - \sum \Delta H_f^\circ(	ext{reactants})$.Given:$\Delta H_f^\circ(CO_{2(g)}) = -393.5 \ kJ/mol$ (since it is the heat of combustion of $C_{(s)}$).$\Delta H_f^\circ(H_2O_{(l)}) = -285 \ kJ/mol$ (since it is the heat of combustion of $H_{2(g)}$).$\Delta H_f^\circ(C_2H_{6(g)}) = -88.2 \ kJ/mol$.$\Delta H_f^\circ(O_{2(g)}) = 0 \ kJ/mol$ (standard state).Substituting the values:$\Delta H_r^\circ = [2 	imes (-393.5) + 3 	imes (-285)] - [-88.2 + 0]$$\Delta H_r^\circ = [-787 - 855] + 88.2$$\Delta H_r^\circ = -1642 + 88.2 = -1553.8 \ kJ/mol$.

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Calculate the enthalpy change for the reaction
$H_2 + F_2 \longrightarrow 2HF$
given that
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Result in $kJ$.

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