What will be the major product of each of the two reactions shown below?
$1.$ $CH_3-CH_2-CH(N^{+}(CH_3)_3)OH^{-} \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$
$2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$

The alkene which on ozonolysis yields acetone is

$Ph-CH=CH_2 \xrightarrow[HBr]{(PhCOO)_2} \text{Product}$
Consider the above reaction:
$A$. The reaction proceeds through a more stable radical intermediate.
$B$. The role of peroxide is to generate $\dot{H}$ (Hydrogen radical).
$C$. During this reaction,benzene is formed as a byproduct.
$D$. $1-\text{Bromo}-2-\text{phenylethane}$ is formed as the minor product.
$E$. The same reaction in the absence of peroxide proceeds via a carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:

Explain the product of the reaction $CH_3CH=CH_2 + HCl \xrightarrow{\text{peroxide}}$

$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[H_2O_2/OH^{-}]{B_2H_6/THF} (Z)$ Major product

The organic compound $5-$allylcyclohex$-3-$ene$-1-$ol is reacted with cold,dilute,aqueous solution of $KMnO_4$. The total number of hydroxyl group$(s)$ $(-OH)$ present in the product is