What will be the input of A and B for the Boo | vedclass

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(A) The given Boolean expression is $Y = \overline {(A + B)} \cdot \overline {(A \cdot B)} = 1$.Using De Morgan's laws, $\overline {(A + B)} = \bar{A}

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(A) The given Boolean expression is $Y = \overline {(A + B)} \cdot \overline {(A \cdot B)} = 1$.Using De Morgan's laws, $\overline {(A + B)} = \bar{A} \cdot \bar{B}$ and $\overline {(A \cdot B)} = \bar{A} + \bar{B}$.Substituting these into the expression: $Y = (\bar{A} \cdot \bar{B}) \cdot (\bar{A} + \bar{B})$.Expanding the expression: $Y = (\bar{A} \cdot \bar{B} \cdot \bar{A}) + (\bar{A} \cdot \bar{B} \cdot \bar{B})$.Since $\bar{A} \cdot \bar{A} = \bar{A}$ and $\bar{B} \cdot \bar{B} = \bar{B}$, we get $Y = (\bar{A} \cdot \bar{B}) + (\bar{A} \cdot \bar{B}) = \bar{A} \cdot \bar{B}$.For $Y = 1$, both $\bar{A}$ and $\bar{B}$ must be $1$.This implies $A = 0$ and $B = 0$.$A$$B$$Y$$0$$0$$1$$0$$1$$0$$1$$0$$0$$1$$1$$0$

What will be the input of $A$ and $B$ for the Boolean expression $\overline {(A + B)} \cdot \overline {(A \cdot B)} = 1$?

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