(A) Let the value in place of the question mark be $x$.Then the equation becomes $\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}$.By cross-multiplying,we

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(A) Let the value in place of the question mark be $x$.Then the equation becomes $\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}$.By cross-multiplying,we get $x^2 = \sqrt{128} \times \sqrt{162}$.$x^2 = \sqrt{128 \times 162}$.$x^2 = \sqrt{(64 \times 2) \times (81 \times 2)}$.$x^2 = \sqrt{64 \times 81 \times 4}$.$x^2 = 8 \times 9 \times 2$.$x^2 = 144$.$x = \sqrt{144} = 12$.

Competitive Quantitative Aptitude Roots of Numbers Squares and Square Roots

Medium

What should come in place of both the question marks in the equation $\frac{?}{\sqrt{128}} = \frac{\sqrt{162}}{?}$?

A
$12$
B
$14$
C
$144$
D
$196$

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Roots of Numbers

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Squares and Square Roots

The least number by which $10584$ must be multiplied to make it a perfect square is

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If $\frac{4 \sqrt{3}+5 \sqrt{2}}{\sqrt{48}+\sqrt{18}}=a+b \sqrt{6},$ then the values of $a$ and $b$ are,respectively

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Given that $\sqrt{13} = 3.605$ and $\sqrt{130} = 11.40$,find the value of $\sqrt{1.3} + \sqrt{1300} + \sqrt{0.013}$.

Medium

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$\frac{112}{\sqrt{196}} \times \frac{\sqrt{576}}{12} \times \frac{\sqrt{256}}{8} = ?$

Easy

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$(x)^{2} \times (12)^{2} \div (48)^{2} = 81$,find the value of $x$.

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What should come in place of both the question marks in the equation $\frac{?}{\sqrt{128}} = \frac{\sqrt{162}}{?}$?

Similar Questions

The least number by which $10584$ must be multiplied to make it a perfect square is

If $\frac{4 \sqrt{3}+5 \sqrt{2}}{\sqrt{48}+\sqrt{18}}=a+b \sqrt{6},$ then the values of $a$ and $b$ are,respectively

Given that $\sqrt{13} = 3.605$ and $\sqrt{130} = 11.40$,find the value of $\sqrt{1.3} + \sqrt{1300} + \sqrt{0.013}$.

$\frac{112}{\sqrt{196}} \times \frac{\sqrt{576}}{12} \times \frac{\sqrt{256}}{8} = ?$

$(x)^{2} \times (12)^{2} \div (48)^{2} = 81$,find the value of $x$.

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