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(A) Given: Diameter of pupil, $d = 2 \,mm = 2 	imes 10^{-3} \,m$. Distance of objects, $D = 20 \,m$. Wavelength of light, $\lambda = 600 \,nm = 6 	i

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$7.32$

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(A) Given: Diameter of pupil, $d = 2 \,mm = 2 	imes 10^{-3} \,m$. Distance of objects, $D = 20 \,m$. Wavelength of light, $\lambda = 600 \,nm = 6 	imes 10^{-7} \,m$.The limit of resolution for a circular aperture (like the pupil of an eye) is given by the Rayleigh criterion:$	heta = \frac{1.22 \lambda}{d}$The minimum separation $y$ between two objects at distance $D$ is given by $y = 	heta 	imes D$.Substituting the values:$y = \frac{1.22 	imes 6 	imes 10^{-7} 	imes 20}{2 	imes 10^{-3}}$$y = 1.22 	imes 6 	imes 10^{-4} 	imes 10 = 7.32 	imes 10^{-3} \,m$$y = 7.32 \,mm$.Thus, the minimum separation the human eye can resolve is $7.32 \,mm$.

What minimum separation between two objects a human eye would be able to resolve, if the eye pupil diameter is $2 \,mm$ and the two objects are $20 \,m$ away from the eye (in $\,mm$)?
(Assume, human eye to be equivalent to a convex lens and consider the average wavelength of light as $600 \,nm$.)

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What minimum separation between two objects a human eye would be able to resolve, if the eye pupil diameter is $2 \,mm$ and the two objects are $20 \,m$ away from the eye (in $\,mm$)?(Assume, human eye to be equivalent to a convex lens and consider the average wavelength of light as $600 \,nm$.)