What is the work done at 300 K for the react | vedclass

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(D) The work done in a chemical reaction is given by the formula $W = -\Delta n_{g} RT$.First,calculate the change in the number of moles of gaseous s

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$1247$

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(D) The work done in a chemical reaction is given by the formula $W = -\Delta n_{g} RT$.First,calculate the change in the number of moles of gaseous species,$\Delta n_{g} = n_{p(g)} - n_{r(g)}$.For the reaction $SO_{2(g)} + \frac{1}{2} O_{2(g)} ightarrow SO_{3(g)}$,$\Delta n_{g} = 1 - (1 + 0.5) = -0.5 \ mol$.Now,substitute the values into the work formula: $W = -(-0.5) 	imes 8.314 	imes 300$.$W = 0.5 	imes 8.314 	imes 300 = 1247.1 \ J$.Note: If the question asks for work done $BY$ the system,it is $1247.1 \ J$. If it asks for work done $ON$ the system,it is $-1247.1 \ J$. Given the options,the magnitude is $1247.1 \ J$.

What is the work done at $300 \ K$ for the reaction?
$SO_{2(g)} + \frac{1}{2} O_{2(g)} \rightarrow SO_{3(g)}$ (in $J$)?
(Given $R = 8.314 \ J \ K^{-1} \ mol^{-1}$)

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What is the work done at $300 \ K$ for the reaction?$SO_{2(g)} + \frac{1}{2} O_{2(g)} \rightarrow SO_{3(g)}$ (in $J$)?(Given $R = 8.314 \ J \ K^{-1} \ mol^{-1}$)