What is the value of the intercept on the y-a | vedclass

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(B) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = k P^{\frac{1}{n}}$.Taking the logarithm on both sides,we get: $\log \f

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$\log k$

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(B) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = k P^{\frac{1}{n}}$.Taking the logarithm on both sides,we get: $\log \frac{x}{m} = \log k + \frac{1}{n} \log P$.Comparing this with the equation of a straight line,$y = mx + c$,where $y = \log \frac{x}{m}$,$x = \log P$,the slope $m = \frac{1}{n}$,and the intercept $c = \log k$.Therefore,the intercept on the $y$-axis is $\log k$.

What is the value of the intercept on the $y$-axis when $\log \frac{x}{m}$ is plotted against $\log P$ in the Freundlich isotherm?

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