What is the value of sqrt[3]{sqrt{441} + sqrt | vedclass

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Question

(A) To find the value of $\sqrt[3]{\sqrt{441} + \sqrt{16} + \sqrt{4}}$,we first evaluate the square roots inside the expression:$\sqrt{441} = 21$$\sqr

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) To find the value of $\sqrt[3]{\sqrt{441} + \sqrt{16} + \sqrt{4}}$,we first evaluate the square roots inside the expression:$\sqrt{441} = 21$$\sqrt{16} = 4$$\sqrt{4} = 2$Now,substitute these values back into the expression:$\sqrt[3]{21 + 4 + 2} = \sqrt[3]{27}$Since $27 = 3 	imes 3 	imes 3 = 3^3$,the cube root of $27$ is:$\sqrt[3]{27} = 3$Therefore,the correct value is $3$.

What is the value of $\sqrt[3]{\sqrt{441} + \sqrt{16} + \sqrt{4}}$?

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