What is the value of frac{(0.5)^{3}-(0.1)^{3} | vedclass

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(B) The given expression is of the form $\frac{a^3 - b^3}{a^2 + ab + b^2}$,where $a = 0.5$ and $b = 0.1$.We know the algebraic identity: $a^3 - b^3 =

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(B) The given expression is of the form $\frac{a^3 - b^3}{a^2 + ab + b^2}$,where $a = 0.5$ and $b = 0.1$.We know the algebraic identity: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$.Substituting this identity into the numerator,we get:$\frac{(a - b)(a^2 + ab + b^2)}{a^2 + ab + b^2} = a - b$.Now,substitute the values of $a$ and $b$:$0.5 - 0.1 = 0.4$.Therefore,the value of the expression is $0.4$.

What is the value of $\frac{(0.5)^{3}-(0.1)^{3}}{(0.5)^{2}+0.5 \times 0.1+(0.1)^{2}}?$

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