What is the total number of -OH groups presen | vedclass

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(D) nucleoside is formed by the combination of a pentose sugar and a nitrogenous base. In $DNA$,the sugar involved is $2$-deoxy-$D$-ribose. In $2$-deo

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$2$

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(D) nucleoside is formed by the combination of a pentose sugar and a nitrogenous base. In $DNA$,the sugar involved is $2$-deoxy-$D$-ribose. In $2$-deoxy-$D$-ribose,the $-OH$ group at the $C-2$ position is replaced by a hydrogen atom. Therefore,the sugar has $-OH$ groups at the $C-3$ and $C-5$ positions. When the nitrogenous base attaches to the $C-1$ position of the sugar,the $-OH$ group at $C-1$ is removed. Thus,the resulting nucleoside (deoxyribonucleoside) contains two $-OH$ groups,one at the $C-3$ position and one at the $C-5$ position.

What is the total number of $-OH$ groups present in a nucleoside involved in the formation of $DNA$?

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