What is the symbol for the nucleus remaining after $_{20}Ca^{42}$ undergoes $\beta$-emission?

  • A
    $_{21}Ca^{42}$
  • B
    $_{20}Sc^{42}$
  • C
    $_{21}Sc^{42}$
  • D
    $_{21}Sc^{41}$

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$C_{6}H_{5}F^{18}$ is an $F^{18}$ radio-isotope labelled organic compound. $F^{18}$ decays by positron emission. The product resulting from the decay is:

During the emission of a $\beta$-particle,what happens to the nucleus?

$A$ radioisotope will not emit

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Which statement is incorrect?

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