What is the shape of the BrF_5 molecule? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The central atom $Br$ has $7$ valence electrons. In $BrF_5$,it forms $5$ bonds with $F$ atoms and has $1$ lone pair of electrons.Total electron pa

Vedclass · Accepted Answer

Square pyramidal

Vedclass · Answer

(C) The central atom $Br$ has $7$ valence electrons. In $BrF_5$,it forms $5$ bonds with $F$ atoms and has $1$ lone pair of electrons.Total electron pairs = $5$ (bond pairs) + $1$ (lone pair) = $6$.This corresponds to $sp^3d^2$ hybridization with octahedral electron geometry.Due to the presence of one lone pair,the shape of the $BrF_5$ molecule is square pyramidal.

What is the shape of the $BrF_5$ molecule?

Similar Questions

Which of the following compounds has the smallest bond angle?

The structure of $XeF_5^-$ is:

The correct order of the bond angles of the compounds $SiCl_4, BF_3, BeCl_2$ and $SF_6$ is

State the contribution of Nyholm and Gillespie in $VSEPR$ theory.

The group having triangular planar structures is

Vedclass Test Series

Exam Paper Generator

Online Exam Module