What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the emf of the cell? When will the maximum work be obtained from a galvanic cell?
(N/A) The relationship between the Gibbs free energy change $(\Delta_{r}G)$ and the cell emf $(E_{cell})$ is given by the equation: $\Delta_{r}G = -nFE_{cell}$.
Here,$n$ is the number of moles of electrons transferred,$F$ is the Faraday constant $(96487 \ C \ mol^{-1})$,and $E_{cell}$ is the cell potential.
Under standard conditions,this is expressed as: $\Delta_{r}G^{\circ} = -nFE^{\circ}_{cell}$.
Maximum work is obtained from a galvanic cell when the cell reaction is carried out reversibly.
Here,$n$ is the number of moles of electrons transferred,$F$ is the Faraday constant $(96487 \ C \ mol^{-1})$,and $E_{cell}$ is the cell potential.
Under standard conditions,this is expressed as: $\Delta_{r}G^{\circ} = -nFE^{\circ}_{cell}$.
Maximum work is obtained from a galvanic cell when the cell reaction is carried out reversibly.
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