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(B) The reaction of nitrobenzene with $Sn + HCl$ is a standard reduction reaction. Nitrobenzene $(C_6H_5NO_2)$ undergoes reduction in the presence of

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Aniline

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(B) The reaction of nitrobenzene with $Sn + HCl$ is a standard reduction reaction. Nitrobenzene $(C_6H_5NO_2)$ undergoes reduction in the presence of a metal-acid catalyst like $Sn + HCl$ to form aniline $(C_6H_5NH_2)$. The chemical equation is: $C_6H_5NO_2 + 6[H] \xrightarrow{Sn+HCl} C_6H_5NH_2 + 2H_2O$ Therefore,the product obtained is aniline.

What is the product obtained in the following reaction?

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