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(C) The peroxide effect (Kharasch effect) is only observed with $HBr$ due to the favorable energetics of the free radical mechanism. $HCl$ has a stron

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Anti-Markovnikov addition for $HBr$ only

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(C) The peroxide effect (Kharasch effect) is only observed with $HBr$ due to the favorable energetics of the free radical mechanism. $HCl$ has a strong $H-Cl$ bond,making the initiation step endothermic. $HI$ forms $I$ radicals that readily combine to form $I_2$ rather than adding to the double bond. Therefore,only $HBr$ shows Anti-Markovnikov addition in the presence of peroxide.

What is the product obtained from the reaction of $HCl$,$HBr$,and $HI$ with alkenes in the presence of peroxide?

Similar Questions

The correct structure of the product $A$ formed in the reaction shown below is:
$Cyclohex-2-en-1-one \xrightarrow[{Pd/C, \text{ ethanol}}]{{H_2 \text{ (gas, 1 atm)}}} A$

Taking into account the stability of various cycloalkanes and carbocations,as well as the rules governing mechanisms of carbocation rearrangements,what is the most likely product of this reaction?

Product $(P)$ is

When ethanol is heated with conc. $H_{2}SO_{4}$,a gas is produced. The compound formed,when this gas is treated with cold dilute aqueous solution of Baeyer's reagent,is:

Ozonolysis of which compound gives $OHC-CH_2-CH(CH_3)-CH_2-CHO$?

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