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Question

(D) leap year consists of $366$ days.$366$ days are equivalent to $52$ weeks and $2$ extra days.These $2$ extra days can be any of the following pairs

Vedclass · Accepted Answer

$\frac{2}{7}$

Vedclass · Answer

(D) leap year consists of $366$ days.$366$ days are equivalent to $52$ weeks and $2$ extra days.These $2$ extra days can be any of the following pairs: (Sunday,Monday),(Monday,Tuesday),(Tuesday,Wednesday),(Wednesday,Thursday),(Thursday,Friday),(Friday,Saturday),or (Saturday,Sunday).There are $7$ possible outcomes for these $2$ extra days.For the year to have $53$ Sundays,one of these $2$ extra days must be a Sunday.From the list of pairs,the favorable outcomes are (Sunday,Monday) and (Saturday,Sunday).Thus,there are $2$ favorable outcomes out of $7$ total possibilities.Therefore,the required probability is $\frac{2}{7}$.

What is the probability that a leap year selected at random will contain $53$ Sundays?

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