What is the physical state of water at $(a)$ $25\,^oC$,$(b)$ $0\,^oC$,and $(c)$ $100\,^oC$?
(N/A) At $0\,^oC$,water exists in a state of equilibrium between solid (ice) and liquid phases. At $100\,^oC$,water exists in a state of equilibrium between liquid and gaseous (steam) phases. Between $0\,^oC$ and $100\,^oC$,water remains in the liquid state.
$(a)$ At $25\,^oC$: Liquid state.
$(b)$ At $0\,^oC$: Solid and liquid state (melting point).
$(c)$ At $100\,^oC$: Liquid and gaseous state (boiling point).
$(a)$ At $25\,^oC$: Liquid state.
$(b)$ At $0\,^oC$: Solid and liquid state (melting point).
$(c)$ At $100\,^oC$: Liquid and gaseous state (boiling point).
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