(D) Let the oxidation number of $Ru$ be $x$.$NH_{3}$ is a neutral ligand (charge $= 0$).$H_{2}O$ is a neutral ligand (charge $= 0$).$Cl$ is a chloride

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(D) Let the oxidation number of $Ru$ be $x$.$NH_{3}$ is a neutral ligand (charge $= 0$).$H_{2}O$ is a neutral ligand (charge $= 0$).$Cl$ is a chloride ion (charge $= -1$).The complex is neutral,so the sum of oxidation states equals $0$.$x + 5(0) + 1(0) + 2(-1) = 0$$x - 2 = 0$$x = +2$Therefore,the oxidation number of $Ru$ is $+2$.