What is the number of moles of nascent hydrog | vedclass

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(C) The reduction of iodomethane $(CH_3I)$ to methane $(CH_4)$ using nascent hydrogen $([H])$ is represented by the following chemical equation: $CH_3

Vedclass · Accepted Answer

$2$

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(C) The reduction of iodomethane $(CH_3I)$ to methane $(CH_4)$ using nascent hydrogen $([H])$ is represented by the following chemical equation: $CH_3I + 2[H] \xrightarrow{Zn, HCl} CH_4 + HI$ From the stoichiometry of the reaction,$1$ mole of iodomethane reacts with $2$ moles of nascent hydrogen to produce $1$ mole of methane. Therefore,the number of moles of nascent hydrogen required is $2$.

What is the number of moles of nascent hydrogen required to prepare $1$ mole of methane from iodomethane?

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