What is the momentum of a photon having frequ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The momentum $p$ of a photon is given by the formula $p = \frac{E}{c}$,where $E = h
u$ is the energy of the photon.Substituting the values,we get

Vedclass · Accepted Answer

$3.3 	imes 10^{-29} \ kg \ m/s$

Vedclass · Answer

(A) The momentum $p$ of a photon is given by the formula $p = \frac{E}{c}$,where $E = h
u$ is the energy of the photon.Substituting the values,we get $p = \frac{h
u}{c}$.Given: $h = 6.6 	imes 10^{-34} \ J \ s$,$
u = 1.5 	imes 10^{13} \ Hz$,and $c = 3 	imes 10^8 \ m/s$.$p = \frac{6.6 	imes 10^{-34} 	imes 1.5 	imes 10^{13}}{3 	imes 10^8}$.$p = \frac{9.9 	imes 10^{-21}}{3 	imes 10^8} = 3.3 	imes 10^{-29} \ kg \ m/s$.

What is the momentum of a photon having frequency $1.5 \times 10^{13} \ Hz$?

Similar Questions

What is the unit of energy in atomic and nuclear physics? Define it.

$n$ photons of wavelength $\lambda$ are absorbed by a black body of mass $m$. The momentum gained by the body is

$A$ photon of wavelength $4400 \, \mathring{A}$ is passing through vacuum. The effective mass and momentum of the photon are respectively

An $AIR$ station is broadcasting waves of wavelength $300 \ m$. If the radiating power of the transmitter is $10 \ kW$,then the number of photons radiated per second is:

The approximate wavelength of a photon of energy $2.48 \,eV$ is ............ $\mathring A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module