What is the molar concentration of acetic aci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: $K_{a} = 1.8 	imes 10^{-5}$ and $\alpha = 0.02$. For a weak monobasic acid,the relationship between dissociation constant $(K_{a})$,degree

Vedclass · Accepted Answer

$4.5 	imes 10^{-2} \ M$

Vedclass · Answer

(B) Given: $K_{a} = 1.8 	imes 10^{-5}$ and $\alpha = 0.02$. For a weak monobasic acid,the relationship between dissociation constant $(K_{a})$,degree of dissociation $(\alpha)$,and molar concentration $(c)$ is given by the formula: $K_{a} = \alpha^2 c$ Rearranging the formula to solve for concentration $(c)$: $c = \frac{K_{a}}{\alpha^2}$ Substituting the given values: $c = \frac{1.8 	imes 10^{-5}}{(0.02)^2} = \frac{1.8 	imes 10^{-5}}{4 	imes 10^{-4}} = 0.45 	imes 10^{-1} \ M = 4.5 	imes 10^{-2} \ M$.

What is the molar concentration of acetic acid if the value of its dissociation constant is $1.8 \times 10^{-5}$ and the degree of dissociation is $0.02$?

Similar Questions

Which of the following will not conduct electricity in aqueous solution?

Calculate the percentage dissociation of a $0.05 \ M$ solution of a weak electrolyte if its molar conductivity and molar conductivity at infinite dilution are respectively $3.3 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and $132 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. (in $\%$)

If a $1.0 \, M$ solution of a weak acid is diluted to $0.01 \, M$ at constant temperature,which of the following will occur?

$A$ weak monobasic acid is $1\%$ ionised in $0.1 \ M$ solution at $25 \ ^{\circ}C$. The $\%$ ionisation in its $0.025 \ M$ solution is

The degree of dissociation in a weak electrolyte increases:

Vedclass Test Series

Exam Paper Generator

Online Exam Module