What is the magnetic moment of a divalent ion | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The atomic number of the element is $28$, which corresponds to Nickel $(Ni)$.The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.A d

Vedclass · Accepted Answer

$2.84$

Vedclass · Answer

(B) The atomic number of the element is $28$, which corresponds to Nickel $(Ni)$.The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.A divalent ion $(Ni^{2+})$ is formed by the loss of two electrons from the $4s$ orbital, resulting in the configuration $[Ar] 3d^8$.In the $3d^8$ configuration, there are $2$ unpaired electrons $(n=2)$.The magnetic moment $(\mu)$ is calculated using the spin-only formula: $\mu = \sqrt{n(n+2)} \ BM$.Substituting $n=2$: $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.84 \ BM$.

What is the magnetic moment of a divalent ion in aqueous solution if its atomic number is $28$ (in $BM$)?

Similar Questions

The complex which does not exhibit geometrical isomerism is

Amongst $TiF_6^{2-}$,$CoF_6^{3-}$,$Cu_2Cl_2$ and $NiCl_4^{2-}$,the colourless species are

The correct order of magnetic moments (spin values in $BM$) among the following is:

How many geometrical isomers are theoretically possible for the complex $[Pt(py)(NH_3)(NO_2)Cl BrI]$?

Select the correct statement$(s)$ regarding the $[Ni(DMG)_2]$ complex compound.

Vedclass Test Series

Exam Paper Generator

Online Exam Module