What is the equivalent weight of methanol if | vedclass

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(A) The balanced chemical equation for the combustion of $CH_3OH$ to $CO$ and $H_2O$ is:$CH_3OH + O_2 \rightarrow CO + 2H_2O$In this reaction,the oxid

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$8$

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(A) The balanced chemical equation for the combustion of $CH_3OH$ to $CO$ and $H_2O$ is:$CH_3OH + O_2 ightarrow CO + 2H_2O$In this reaction,the oxidation state of carbon in $CH_3OH$ is $-2$ and in $CO$ is $+2$.The change in oxidation state of carbon is $|2 - (-2)| = 4$.Thus,the valency factor ($n$-factor) for methanol is $4$.The molecular weight of $CH_3OH$ is $12 + 4(1) + 16 = 32 \ g/mol$.Equivalent weight = $\frac{	ext{Molecular weight}}{n	ext{-factor}} = \frac{32}{4} = 8$.

What is the equivalent weight of methanol if one mole of $CH_3OH$ is combusted to form $CO$ and $H_2O$?

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