What is the effective atomic number (EAN) of | vedclass

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(C) The effective atomic number $(EAN)$ is calculated using the formula: $EAN = Z - X + Y$,where $Z$ is the atomic number of the metal,$X$ is the oxid

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(C) The effective atomic number $(EAN)$ is calculated using the formula: $EAN = Z - X + Y$,where $Z$ is the atomic number of the metal,$X$ is the oxidation state of the metal,and $Y$ is the number of electrons donated by the ligands.For $[Fe(CN)_6]^{4-}$:$Z = 26$ (for $Fe$).Let the oxidation state of $Fe$ be $x$. Then $x + 6(-1) = -4$,which gives $x = +2$. So,$X = 2$.Since $CN^-$ is a monodentate ligand,$6$ ligands donate $6 	imes 2 = 12$ electrons. So,$Y = 12$.$EAN = 26 - 2 + 12 = 36$.

What is the effective atomic number $(EAN)$ of $Fe$ in $[Fe(CN)_6]^{4-}$? (Atomic number of $Fe = 26$)

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