What is the difference in molar masses of the | vedclass

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(B) The general formula for the alkane series is $C_nH_{2n+2}$.For the third homologue $(n=3)$,the formula is $C_3H_8$,and its molar mass is $(3 	ime

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$14 \ g \ mol^{-1}$

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(B) The general formula for the alkane series is $C_nH_{2n+2}$.For the third homologue $(n=3)$,the formula is $C_3H_8$,and its molar mass is $(3 	imes 12) + (8 	imes 1) = 44 \ g \ mol^{-1}$.For the fourth homologue $(n=4)$,the formula is $C_4H_{10}$,and its molar mass is $(4 	imes 12) + (10 	imes 1) = 58 \ g \ mol^{-1}$.Any two successive homologues in an alkane series differ by a $-CH_2-$ group.The molar mass of a $-CH_2-$ group is $12 + (2 	imes 1) = 14 \ g \ mol^{-1}$.Therefore,the difference in molar masses is $58 - 44 = 14 \ g \ mol^{-1}$.

What is the difference in molar masses of the third and fourth homologues of the alkane series?

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