What is the correct IUPAC name of the coordin | vedclass

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(A) $1$. The given coordination compound is $	ext{Hg[Co(SCN)}_4]$.$2$. The compound dissociates into $	ext{Hg}^{2+}$ and $	ext{[Co(SCN)}_4]^{2-}$.$

Vedclass · Accepted Answer

Mercury$(II)$ tetrathiocyanato-$S$-cobaltate$(II)$

Vedclass · Answer

(A) $1$. The given coordination compound is $	ext{Hg[Co(SCN)}_4]$.$2$. The compound dissociates into $	ext{Hg}^{2+}$ and $	ext{[Co(SCN)}_4]^{2-}$.$3$. In the complex anion $	ext{[Co(SCN)}_4]^{2-}$,the ligand is thiocyanate $(SCN^-)$,which is bonded through the sulfur atom,hence it is named 'thiocyanato-$S$'.$4$. Let the oxidation state of cobalt $(Co)$ be $x$. Since the charge on the complex is $-2$ and the charge on $SCN^-$ is $-1$,we have: $x + 4(-1) = -2$,which gives $x = +2$.$5$. The cation is mercury,which is in the $+2$ oxidation state,so it is named 'Mercury$(II)$'.$6$. The complex anion is named 'tetrathiocyanato-$S$-cobaltate$(II)$' because the metal is in an anionic complex.$7$. Combining these,the correct $IUPAC$ name is 'Mercury$(II)$ tetrathiocyanato-$S$-cobaltate$(II)$'.

What is the correct $IUPAC$ name of the coordination compound $\text{Hg[Co(SCN)}_4]$?

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