What is the concentration (in mol L^{-1}) of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a zero-order reaction,$A \longrightarrow 3B$,the rate law is $[A] = [A]_0 - kt$.From the table,at $t = 15 \ s$,$[A] = 0.05 \ mol \ L^{-1}$ and

Vedclass · Accepted Answer

$1.98 	imes 10^{-1}$

Vedclass · Answer

(C) For a zero-order reaction,$A \longrightarrow 3B$,the rate law is $[A] = [A]_0 - kt$.From the table,at $t = 15 \ s$,$[A] = 0.05 \ mol \ L^{-1}$ and $[A]_0 = 0.1 \ mol \ L^{-1}$.Substituting these values: $0.05 = 0.1 - k(15) \implies 15k = 0.05 \implies k = \frac{0.05}{15} = \frac{1}{300} \ mol \ L^{-1} \ s^{-1}$.Now,at $t = 20 \ s$,the concentration of $A$ is $[A] = [A]_0 - kt = 0.1 - (\frac{1}{300}) 	imes 20 = 0.1 - \frac{20}{300} = 0.1 - 0.0667 = 0.0333 \ mol \ L^{-1}$.The amount of $A$ reacted is $\Delta[A] = [A]_0 - [A] = 0.1 - 0.0333 = 0.0667 \ mol \ L^{-1}$.According to the stoichiometry $A \longrightarrow 3B$,the concentration of product $B$ formed is $3 	imes \Delta[A] = 3 	imes 0.0667 = 0.2001 \ mol \ L^{-1}$.Rounding to the nearest option,we get $0.198 \ mol \ L^{-1}$ or $1.98 	imes 10^{-1} \ mol \ L^{-1}$.

Similar Questions

At high pressure,the following reaction is zero order:
$2NH_{3(g)} \xrightarrow[Pt \ \text{catalyst}]{1130 \ K} N_{2(g)} + 3H_{2(g)}$
Choose the option which is not true with respect to the reaction,from the choices given below:

In a reaction,reactant $A$ decomposes $10 \%$ in $1 \ hour$,$20 \%$ in $2 \ hours$ and $30 \%$ in $3 \ hours$. The unit of rate constant of this reaction is

For a zero order reaction $A \longrightarrow \text{product}$,consider the following graph:
Where $[A_t]$ is the remaining concentration of reactant $A$ at time $t$. Calculate the concentration of $A$ after $2 \ s$. (in $mol/L$)

For a zero order reaction,the plot of concentration $(a - x)$ $vs$ time is linear with

For a zero order reaction,a plot of $t_{1/2}$ versus $[A]_0$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module