What is the binding energy of ${ }_{14}^{29} Si$ whose atomic mass is $28.976495 u$ (in $MeV$)?
Mass of proton $= 1.007276 u$
Mass of neutron $= 1.008664 u$
(Neglect the electron mass) (Assume $1 u = 931.5 MeV$)

Draw conclusions from the two main features of the graph of binding energy per nucleon versus the atomic mass number $(A)$.

The graph shows the binding energy per nucleon versus mass number. $A, B, C, D, E, F$ are different nuclei. Four processes are given where $\varepsilon$ is the energy released. In which process is $\varepsilon > 0$?
$(i) \, A + B \rightarrow C + \varepsilon$
$(ii) \, C \rightarrow A + B + \varepsilon$
$(iii) \, D + E \rightarrow F + \varepsilon$
$(iv) \, F \rightarrow D + E + \varepsilon$

The radionuclide $^{11}_{6}C$ decays by $\beta^+$ emission. Given that $m(^{11}_{6}C) = 11.011434 \ u$,$m(^{11}_{5}B) = 11.009305 \ u$,$m_e = 0.000548 \ u$,and $1 \ u = 931.5 \ MeV/c^2$. The $Q$-value of this decay process is:

One atomic mass unit is equivalent to .............. $MeV$ energy.

Let $m_p$ be the mass of a proton,$m_n$ the mass of a neutron,$M_1$ the mass of a ${}_{10}^{20}Ne$ nucleus,and $M_2$ the mass of a ${}_{20}^{40}Ca$ nucleus. Then: