What is the H.C.F. of frac{4}{9}, frac{10}{21 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the $H.C.F.$ of fractions,we use the formula:$H.C.F. = \frac{H.C.F. 	ext{ of numerators}}{L.C.M. 	ext{ of denominators}}$Given fractions

Vedclass · Accepted Answer

$\frac{2}{63}$

Vedclass · Answer

(C) To find the $H.C.F.$ of fractions,we use the formula:$H.C.F. = \frac{H.C.F. 	ext{ of numerators}}{L.C.M. 	ext{ of denominators}}$Given fractions: $\frac{4}{9}, \frac{10}{21}, \frac{20}{63}$Step $1$: Find the $H.C.F.$ of the numerators $(4, 10, 20)$:Factors of $4 = 2 	imes 2$Factors of $10 = 2 	imes 5$Factors of $20 = 2 	imes 2 	imes 5$The common factor is $2$. So,$H.C.F. = 2$.Step $2$: Find the $L.C.M.$ of the denominators $(9, 21, 63)$:$9 = 3^2$$21 = 3 	imes 7$$63 = 3^2 	imes 7$$L.C.M. = 3^2 	imes 7 = 9 	imes 7 = 63$.Step $3$: Combine the results:$H.C.F. = \frac{2}{63}$.

What is the $H.C.F.$ of $\frac{4}{9}, \frac{10}{21}$ and $\frac{20}{63}$?

Similar Questions

The traffic lights at three different road crossings change after $24$ seconds,$36$ seconds,and $54$ seconds,respectively. If they all change simultaneously at $10:15:00$ am,then at what time will they again change simultaneously?

The $L.C.M.$ of two numbers is $120$ and their $H.C.F.$ is $10.$ Which of the following can be the sum of those two numbers?

Three numbers which are co-prime to each other are such that the product of the first two is $551$ and that of the last two is $1073$. The sum of the three numbers is:

Find the least number of five digits which when divided by $8, 12, 16$ and $20$ leaves remainders $1, 5, 9$ and $13$ respectively.

Three pieces of timber $42 \ m$,$49 \ m$,and $63 \ m$ long have to be divided into planks of the same length. What is the greatest possible length of each plank (in $m$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module